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Many students find it difficult to score high marks in Physics. 7. JEE Main Physics Previous Year Questions With Solutions on Thermodynamics ΔQ = ΔU + ΔW Change in internal energy ΔU = ΔQ = 8.4 x 103 J = 8.4 kJ Answer: (b) 8.4 kJ Q9: 200 g water is heated from 40° C to 60 °C. It will help you to boost your confidence level. Designed as per the students’ perspective, it is a premium book to support the dream of leading success in the upcoming JEE MAIN. Electrostatics. IIT - JEE Main Important Questions of Thermodynamics Check all Solved Important Questions of Thermodynamics for the preparation of JEE Main Physics Previous Year Papers Download Solved Question Papers Free for Offline Practice and view Solutions Online. 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